#!/usr/bin/env python3
# -*- indent-tabs-mode: nil -*- vi: set expandtab:

"""
NAME
       yamltojson - convert a yaml file to a json file

SYNOPSIS
       yamltojson file.yaml ...

DESCRIPTION
       Read  in a yaml file (whose name must end with ".yaml") and create cor‐
       responding json files, whose names will end with ".json".
"""

import sys, re, yaml
try:
    import simplejson as json
except:
    import json

def die(msg):
    """ generate a FATAL message to stdout and exit """
    print("%s:FATAL:%s" % (date(), msg))
    sys.exit(2)

for fname in sys.argv[1:]:
    if fname.endswith(".yaml"):
        y = None
        with open(fname, "r") as fd:
            try:
                contents = fd.read()
                contents = re.sub("^\t+", "    ", contents, flags=re.M)
                y = yaml.safe_load(contents)
            except:
                die("Invalid yaml in '%s'" % fname)
        jsonfname = fname[:-5] + ".json"
        with open(jsonfname, "w") as fd:
            json.dump(y, fd, indent=4, sort_keys=True)